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6d^2-13d-8=0
a = 6; b = -13; c = -8;
Δ = b2-4ac
Δ = -132-4·6·(-8)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-19}{2*6}=\frac{-6}{12} =-1/2 $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+19}{2*6}=\frac{32}{12} =2+2/3 $
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